Re: PHP preg_match question

Possibly:

    $vaidateStr = "this is a test 1"; // not valid, contains spaces..
    $compared = preg_replace("/[^a-z0-9\+\-]/", "", $vaidateStr);
    $is_validated = $vaidateStr == $compared;

    if ($is_validated) {
        echo "valid<br />\n";
    }
    else {
        echo "not valid<br />\n";
    }

//
//OR just use (fewer lines, harder to read, etc)
//

    if ($vaidateStr == preg_replace("/[^a-z0-9\+\-]/", "", $vaidateStr)) {
        echo "valid<br />\n";
    }
    else {
        echo "not valid<br />\n";
    }

Ben

On Wed, Jul 20, 2011 at 8:34 PM, keith smith <klsmith2020@yahoo.com> wrote:

>
> Hi,
>
> I have an input string that should only be lower or upper alphas, numbers
> and can contain a hyphen.
>
> I'm trying to figure out how to get PHP preg_match to verify the input
> string only contains these chars.
>
> I tried some thing like this and it always returns true if I have one or
> more of the specified chars, even if I have a char that is not specified.
>
> I need a true for any string that contains Alphas and/or numbers and/or one
> or more hyphens. I need it to return if the string contains anything else.
>
> preg_match("/[a-z0-9\+\-]/", $vaidateStr)
>
> I do not need to use preg_match, I'm looking for a simple solution.
>
> Any pointers are much appreciated.
>
> ------------------------
> Keith Smith
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--
---
Ben

*print ''.join(map(lambda x: chr(x), ( (ord('a')-(3*5)),
int(math.sqrt(math.pi*76)*5+2), int(math.ceil(math.e)*28),
int(math.floor(math.e)*35), long(abs(4%3*35+3)*2))))*
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