Understanding IP class range.
Keith Smith
techlists at phpcoderusa.com
Mon Aug 31 08:51:56 MST 2015
Very nice Kenn!!
Ok so if I had 192.168.1.0/25 the range would be 192.168.1.0 -
192.168.1.127
/26 would be 192.168.1.0 - 192.168.1.192 ? or is it 192.168.1.0 -
192.168.1.64 ?
Is that correct?
Not sure how to make a net mask out of 192.168.1.0/25 - would it be
255.255.255.128?
Thanks!!
On 2015-08-31 02:55, parabellum7 at yahoo.com wrote:
> Hi Keith,
>
> If I recall correctly, the /24 part of 192.168.0.0/24 is the subnet
> specified in CIDR notation (Classless Inter Domain Routing).
>
> Think in binary terms, that /24 equals
> 11111111.11111111.11111111.00000000 (note there's 24 1's) equals
> 255.255.255.0 so is a class C subnet with the first three octets being
> the network mask.
>
> Likewise if you had an IP addy followed by a /8 that equals
> 11111111.00000000.00000000.00000000 equals 255.0.0.0 so is a class A
> subnet.
>
> Called octets cuz there's 8 bits hence a decimal max of 255.
>
> CIDR is usually seen at ISP's or in enterprise networks that need to
> subnet further as the network mask does not have to align with the
> octet boundary as it does in the classfull network addressing we're
> used to. That's where things get weird and all this because those
> silly routers only speak binary. :]
>
> If you're seeing 192.168.0.0/24 in a zenmap target field it means scan
> everything from and including 192.168.0.0 to 192.168.0.255.
>
>
> IP network classes or Classfull Network Addressing
>
> - Range - - mask - # of networks # of nodes CIDR mask
> A 1.1.1.1 - 126.255.255.255 255.0.0.0 126 16,777,214 /8
> B 128.0.0.1 - 191.255.255.255 255.255.0.0 16,384 65,534 /16
> C 192.0.0.1 - 223.255.255.255 255.255.255.0 2,097,151 254 /24
> D 224.0.0.1 - 239.255.255.255
> E 240.0.0.1 - 255.255.255.255
>
>
>
> --Kenn
>
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Keith Smith
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