how to reference bash variables inside perl script inside bash script?

[Brian Cluff]

On 06/23/2010 09:44 PM, Steven A. DuChene wrote:
> The core part of the script I am having a problem with looks like:
>
> #!/bin/bash
>
> OPASS=$2
>
> PASS=`perl -e 'print("userPassword: {CRYPT}".crypt("$OPASS","frat-salt")."\n");'`

Try changing it to this:

PASS=`perl -e 'print("userPassword: 
{CRYPT}".crypt("'$OPASS'","frat-salt")."\n");'`

That change is to add single quotes around the bash variable, the idea 
is that you have to turn off the quoting log enough allow bash to be 
able to insert a variable and then turn it back on so everything else 
will work correctly.  It doesn't work in most other languages, but bash 
isn't like most other languages :)

Brian Cluff