Perl question: passing in variables

[Mike Schwartz]

On 7/6/07, Vaughn Treude <vltreude at deru.com> wrote:
>
> Quick perl question:
> I'm trying to run a perl script that is executable; that is, the file
> has "x" permission and starts with this line:
>
> #!/usr/bin/perl -w
>
> There's a parameter in this script that's not defined by default, for
> example
>
> my $foo; # no default
>
> If foo is not set, the script exits with an error.  Normally I would
> just modify the script but this script gets extracted from a shell
> script that has the perl script and an rpm embedded in it.  (How they
> did that I don't know.)  So I would expect there's a way to do this, but
> there were  no help files with the script.
>
> The shell script invokes the install file like this:
> ./install_script *$
>
> So I know that I can pass one or more arguments to the outer shell
> script and they will get passed verbatim to the perl script.
>
> Is there a to pass a value for foo into the script without modifying the
> script?
>
> Thanks in advance,
> Vaughn
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I do not know Perl,
but maybe if you find a perl FAQ on the web,
you can search for something about a
   "persistent variable"
or s. like that...  if that's what it is.
Just a guess, from
-- 
Mike Schwartz
Glendale  AZ
schwartz at acm.org
Mike.L.Schwartz at gmail.com
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