Faster perl operation?

[JT Moree]

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Joshua Zeidner wrote:
>
>   Jerry, I had the same idea, but are you sure that this operation will
> not allocate a new buffer and copy the entire string( essentially
> eliminating the benefit )?

Is there a pattern to the output?  Is the next one always longer than
the last one?  If so just add the difference onto the last one

my $variable = ".";
while (whatever)
{
  $diff = "." x ($start - 1 - (length $variable));
  $variable .= $diff;
}

- --
JT Morée
PC Xperience, Inc.
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