right.... I knew that! lol

:-)~MIKE~(-:

On Thu, Feb 26, 2015 at 9:12 AM, Todd Millecam <tyggna@gmail.com> wrote:

well, I meant pin numbers, which are usually 4 digits, so only try 1000 numbers at a time

On Thu, Feb 26, 2015 at 9:10 AM, Michael Havens <bmike1@gmail.com> wrote:

What do you mean by 'pins'? Is that like 'groups of 1000'?

It finally finished after about 5 hours.

:-)~MIKE~(-:

On Thu, Feb 26, 2015 at 2:12 AM, Todd Millecam <tyggna@gmail.com> wrote:

to thread it out, change the ; before done to a &

It'd also be a good idea to only do 1000 pins at a time for that.

for i in `seq 1111 2111` ; do echo "password $i" | netcat server port & done

for i in `seq 2112 3112`; . . .

On Wed, Feb 25, 2015 at 11:30 PM, Michael Havens <bmike1@gmail.com> wrote:

I had to redirect the output of that script to a file I can manipulate later. I think I will have to sort the file and then run uniq on it as it will be 10000 lines (did I miss a zero?) minus one of:

I am the pincode checker for user bandit25. Please enter the password for user bandit24 and the secret pincode on a single line, separated by a space.

Wrong! Please enter the correct pincode. Try again.

Exiting.

Or else, the 'Wrong....'  says 'Right....' on one line (or something like that) and I just need to search for an affirmation word

:-)~MIKE~(-:

On Wed, Feb 25, 2015 at 6:40 PM, Michael Havens <bmike1@gmail.com> wrote:

the man pages never would have taught me that! I really need to learn to program before I start the other wargames. that is just bash scripting?

:-)~MIKE~(-:

On Wed, Feb 25, 2015 at 10:48 AM, Todd Millecam <tyggna@gmail.com> wrote:

Your program is the wrong way to do this.  For 1 mil + guesses, C is the right way to go, but for 10k you can just use a shell script:

for i in `seq 1111 9999` ; do echo "password $i" |  netcat server.com 30002 ; done

Why do I feel like I'm helping you cheat?

On Wed, Feb 25, 2015 at 10:26 AM, Michael Havens <bmike1@gmail.com> wrote:

The instructions they give are:

A daemon is listening on port 30002 and will give you the password for bandit25 if given the password for bandit24 and a secret numeric 4-digit pincode. There is no way to retrieve the pincode except by going through all of the 10000 combinaties, called brute-forcing.

I figure I'd netcat to the port a file with the bandit24's password and the pincodes and .... I still have to investigate man  more

:-)~MIKE~(-:

On Wed, Feb 25, 2015 at 10:05 AM, Mark Phillips <mark@phillipsmarketing.biz> wrote:

Mike,

I don't think the program you found prints anything. What were the actual instructions from Bandit?

Mark

On Wed, Feb 25, 2015 at 8:22 AM, druid001 . <dtroyer1@gmail.com> wrote:

Can't help, but what a coincidence, I just started bandit last night!

On Wed, Feb 25, 2015 at 1:51 AM, Michael Havens <bmike1@gmail.com> wrote:

I need to get every four digit combination as part of the next challenge in bandit. I'm not a programmer so I googled for a solution. Please, how do I run this program?

int main(int argc, char** argv){
int a,b,c,d;

for(a=1; a<5; a++){
for(b=1; b<5; b++){
for(c=1; c<5; c++){
for(d=1; d<5; d++){
if(!(a==b || a==c || a==d || b==c || b==d || c==d))
printf("%d%d%d%d
",a,b,c,d);
}
}
}
}

return 0;
}

:-)~MIKE~(-:

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