Ah yes, I also forgot the uppercase chars

    if ($vaidateStr == preg_replace("/[^a-zA-Z0-9\-]/", "", $vaidateStr)) {
       /true, or valid...
    }

BTW also as Eric says, the carrot (^) inside the square brackets means "anything but" (negation), thus how this works..

Ben

On Wed, Jul 20, 2011 at 9:38 PM, Eric Cope <eric.cope@gmail.com> wrote:
Here is the regular expression:

/^[a-zA-Z0-9\-]+$/

the ^ requires the pattern match at the beginning of the string.
The + requires at least one of these characters, but no upper limit. You can use * if you don't need the lower limit of 1.
$ requires the patten match all the way to the end of the string.
The dash requires escaping, hence the back slash.

http://www.regular-expressions.info/anchors.html

Thanks,
Eric

On Wed, Jul 20, 2011 at 8:34 PM, keith smith <klsmith2020@yahoo.com> wrote:

Hi, 

I have an input string that should only be lower or upper alphas, numbers and can contain a hyphen. 

I'm trying to figure out how to get PHP preg_match to verify the input string only contains these chars.

I tried some thing like this and it always returns true if I have one or more of the specified chars, even if I have a char that is not specified.

I need a true for any string that contains Alphas and/or numbers and/or one or more hyphens.  I need it to return if the string contains anything else.

preg_match("/[a-z0-9\+\-]/", $vaidateStr)

I do not need to use preg_match, I'm looking for a simple solution.

Any pointers are much appreciated.

------------------------
Keith Smith

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--
---
Ben

print ''.join(map(lambda x: chr(x), ( (ord('a')-(3*5)), int(math.sqrt(math.pi*76)*5+2), int(math.ceil(math.e)*28), int(math.floor(math.e)*35), long(abs(4%3*35+3)*2))))