awk '$2~/170/ {print}' filename

On Tue, Apr 14, 2009 at 6:34 PM, Jim March <1.jim.march@gmail.com> wrote:
Guys,

I have an interesting database problem that I think can be solved on
the command line in one shot.  But I don't know how :(.

I have a comma separated values text file.  Each line shows a voter ID
number and an election ID number they voted in.  NOT who they voted
for, and not their names, just that they voted in that election (cast
a ballot at all, even if blank).

There are multiple elections a given voter likely voted for.  So
here's the section for two voter IDs (first column) and the elections
they voted in (second column) plus the method used to vote (third
column) if it was early or mail-in (which I can ignore).  In pasting
it to EMail (from Openoffice spreadsheet used as a quick viewer)
they're separated by spaces but in the original data it's commas.

---
233     2
233     3
233     4
233     5
233     6
233     7
233     31
233     32
233     38
233     41
233     45
233     55
233     57
233     95
233     96
235     2
235     3
235     4
235     5
235     6
235     7
235     31      Early Ballot
235     32      Early Ballot
235     38
235     45
235     55
235     57      Early Ballot
235     95      Early Ballot
235     96      Early Ballot
235     125
235     126     Early Ballot
235     143
235     147     Early Ballot
235     148     Early Ballot
235     170     Early Ballot
---

So what I want to do is, strip out every line that does NOT have a
"170" in the second column, and then produce a line count.  I need to
know (like ASAP) how many people voted in election 170 as that's the
2006 RTA special election in Pima County now subject to a recount.
And then I can do a second pass using the same technique and find out
how many people filed an early ballot by stripping out those and
counting lines again (and doing basic subtraction).

Help?  This is about a criminal ivestigation going on right now
regarding this election...

Thanks!

Jim March
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--
James McPhee
jmcphe@gmail.com