I think its safe to assume 1010 is binary which would put em around 42

so that would make me 5C divided by 4

-Scott






FoulDragon@aol.com
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08/02/2005 03:04 PM
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Re: Anyone around 18 in the group?





In a message dated 8/2/2005 2:34:54 PM US Mountain Standard Time, rw@xend.net
writes:

> I'm at its 2nd harmonic plus 5 mhz.
> Daniel
>
Another one for me:  I'm roughly 1010 times the Sqrt of 18.

1010 sqrt (18)?  That would make you well over four thousand years old.

Let me put it this way:  When I was 18, the 2.2 kernel was new and exciting,
a K6-2-400 cost a semester's scholarship money, and my present keyboard was
two years old already.
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