in perl you can do something like /e(?{$i++})/{if $i>3 print $_;$i=0} no
time to code and debug though.  i guess the title of regex MASTER goes to
Jeremy for now.  jmz


On 4/5/06, Darrin Chandler <dwchandler@stilyagin.com> wrote:
>
> Darrin Chandler wrote:
>
> > Kevin Brown wrote:
> >
> >>> egrep -i '^[^e]*(e[^e]*){3}[^e]*$'
> >>>
> >>> Not only is it slightly shorter and more readable, but it's a lot
> >>> easier change it to search for of 'e' exactly n times.
> >>
> >>
> >>
> >> If I'm reading the regexp correctly you are excluding words that
> >> start with e or contain more than one e in a row.
> >
> >
> >
> > Read it some more ;)
> >
>
> Okay, maybe it's *not* more readable for most. I think it'd fly on
> phoenix.pm without much trouble.
>
> It does work and it's easier to change for different numbers of 'e'.
>
> --
> Darrin Chandler            |  Phoenix BSD Users Group
> dwchandler@stilyagin.com   |  http://bsd.phoenix.az.us/
> http://www.stilyagin.com/  |
>
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