awk.

cat file | awk '{print "z=z+"$1}'

Proof:
bob@donelle:~> printf " 1234960\n1456780\n3456567\n5476865\n456098\n" | awk
'{print "z=z+"$1}'
z=z+1234960
z=z+1456780
z=z+3456567
z=z+5476865
z=z+456098
bob@donelle:~> 

BTW - you are prepending, not appending.

George



Support wrote:
> 
> HI
> 
> Any sed gurus on the list? I use it often in a class I am taking but I
> am stuck on this one and have had no luck with the docs I have found.
> What I need to do is append 'z=z+' to the beginning of every line in a
> file.
> 
> The file looks like this:
> 
>                  1234960
>                 1456780
>                 3456567
>                 5476865
>                 456098
> 
> thats it 1 simple column! Maybe I need some sleep it is 1 am here in
> Germany.
> 
> Thanks for any help!
> (I know you are out there der hans) :)
> 
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