Here is one of my tools that accomplishes what you want. It will 
convert to/from any base 2-16.

i.e. 

$ baseconv 255 16			(decimal 255 to hex)
255 in base 16 is: ff

$ baseconv 255 2			(decimal 10 255 to binary)
255 in base 2 is:  1111 1111

$ baseconv 0x255 10		(hex to decimal)
0x255 in base 10 is: 597

$ baseconv /13 10			(octal to decimal)
/13 in base 10 is: 11


To use cut/paste, compile, enjoy.

Command line rules!

John Gorman

---[ BEGIN CUT ]----------------------------------------------------

#include <stdio.h>
#include <stdlib.h>

/********************************************************************
 *
 * Function:    baseconv
 *
 * Author:      John Gorman (JHGorman@yahoo.com)
 *
 * Created:     7/23/1998
 *
 * Description: This program will accept as input 2 values
 *              the first value will be a number (base-10) 
 *              the second number will be a base in which to 
 *              display the first value
 *
 * Input:       int number (base-10)
 *              int base   (2-16)
 *
 * Output:      string representing the base-10 value in the
 *              base requested in input value 2
 *
 * Updates:     Oct 23, 1998, John Gorman
 *              -- Added the ability to accept an octal number
 *
 *******************************************************************
*/

char* baseconv(unsigned long num, int base)
{
static char retbuf[100];

char *p;

int iCnt=0;

if (base < 2 || base > 16)
  {
    return NULL;
  }

p = &retbuf[sizeof(retbuf)-1];
*p = '\0';

do 
  {
    *--p = "0123456789abcdef"[num % base];
    num /= base;
    
    if (base == 2)
      {
        iCnt++;
        if ( (iCnt %4) == 0)
          {
            *--p = ' ';
          }
      }
  }
 while(num != 0);

 return p;

}

void main(int argc, char *argv[])
{
int number;
int base;

unsigned long lNumber;

char *result;
char *endptr;

if (argc == 3)
  {
    base   = atoi(argv[2]);
    if (argv[1][0] == '0' && argv[1][1] == 'x')
      {
        number = lNumber = strtoul(argv[1], &endptr, 16);
      }
    else if (argv[1][0] == '/')
      {
        number = lNumber = strtoul(argv[1]+1, &endptr,8);
      }
    else
      {
        number = lNumber = strtoul(argv[1], &endptr,10);
        /*number = atoi(argv[1]);*/
      }
  }
else
  {
    printf("\nusage: %s number base(2-16)\n", argv[0]);
    printf("       where number is either a base 10 number, OR\n");
    printf("       a base 16 number (i.e. 0xf1),            OR\n");
    printf("       a base  8 number (i.e. /32)\n\n");
    exit(-1);
  }


result = baseconv(lNumber, base);

printf("%s in base %d is: %s\n", argv[1], base, result);

return;
}
---[ END CUT   ]----------------------------------------------------

-----Original Message-----
From: Lucas Vogel [mailto:lvogel@exponent.com]
Sent: Tuesday, February 06, 2001 7:04 PM
To: 'plug-discuss@lists.plug.phoenix.az.us'
Subject: looking for a program


I'm looking for a program that will take either a decimal, hex or octal
input and give me its decimal, hex or octal output. Can anyone tell me what
I'm looking for? 

Lucas "I Spy" Vogel

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