Am 06. Feb, 2001 schwäzte Kevin Buettner so:

Kevin,

you're posts are just *too* cool! :)

Now since I don't use debuggers other than those that have been blessed by
Linus, e.g. print statements :), I don't know the intricacies of gdb.

Since you're basically throwing it a line of code in a command line type
of way it seems like you kind of have a shell for c/c++ and whatever else
gdb understands. Is that somewhat correct?

If so, can you toss it a few lines of code, specifically a loop or other
control block to test it out. Sort of like a "for i in ..." construct from
a shell command line?

Can you include files, then run stuff?

I'm starting to look at c stuff again ( that's what I'm planning for my
spare nano-second this year ;-), so if I could do some of those stupid
shell tricks from a c 'command line' I could practice doing them in c :).

ciao,

der.hans

> On Feb 6,  6:03pm, Lucas Vogel wrote:
> 
> > I'm looking for a program that will take either a decimal, hex or octal
> > input and give me its decimal, hex or octal output. Can anyone tell me what
> > I'm looking for? 
> 
> Like others who've answered, the first thing I thought of was
> Perl...
> 
>     saguaro:kev$ perl -e 'printf "%x\n", 42'
>     2a
>     saguaro:kev$ perl -e 'printf "%d\n", 0x2a'
>     42
>     saguaro:kev$ perl -e 'printf "%o\n", 0x2a'
>     52
>     saguaro:kev$ perl -e 'printf "%d\n", 052'
>     42
> 
> But gdb works good for this purpose too...
> 
>     saguaro:kev$ gdb
>     GNU gdb 5.0
>     [...]
>     (gdb) print/x 42
>     $1 = 0x2a
>     (gdb) print 0x2a
>     $2 = 42
>     (gdb) print/o 0x2a
>     $3 = 052
>     (gdb) print 052
>     $4 = 42
>     (gdb) 
> 
> gdb makes a pretty good calculator too...
> 
>     (gdb) print/x 6*7
>     $5 = 0x2a
>     (gdb) print $5/7  
>     $6 = 6
>     (gdb) print $5+$6
>     $7 = 48
> 
> And for you C/C++ programmers out there...
> 
>     (gdb) print &((int *) 0)[4]
>     $8 = (int *) 0x10
>     (gdb) print/d &((int *) 0)[4]
>     $9 = 16
> 
> (This'd be the byte offset of the fourth element in an int array.  Of
> course, the results are target dependent.)
> 
> Kevin
> 
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