how do I run this program?

[Todd Millecam]

Your program is the wrong way to do this.  For 1 mil + guesses, C is the
right way to go, but for 10k you can just use a shell script:

for i in `seq 1111 9999` ; do echo "password $i" |  netcat server.com 30002
; done

Why do I feel like I'm helping you cheat?

On Wed, Feb 25, 2015 at 10:26 AM, Michael Havens <bmike1 at gmail.com> wrote:

> The instructions they give are:
>
> A daemon is listening on port 30002 and will give you the password for
> bandit25 if given the password for bandit24 and a secret numeric 4-digit
> pincode. There is no way to retrieve the pincode except by going through
> all of the 10000 combinaties, called brute-forcing.
>
> I figure I'd netcat to the port a file with the bandit24's password and
> the pincodes and .... I still have to investigate man  more
> :-)~MIKE~(-:
>
> On Wed, Feb 25, 2015 at 10:05 AM, Mark Phillips <
> mark at phillipsmarketing.biz> wrote:
>
>> Mike,
>>
>> I don't think the program you found prints anything. What were the actual
>> instructions from Bandit?
>>
>> Mark
>>
>> On Wed, Feb 25, 2015 at 8:22 AM, druid001 . <dtroyer1 at gmail.com> wrote:
>>
>>> Can't help, but what a coincidence, I just started bandit last night!
>>>
>>> On Wed, Feb 25, 2015 at 1:51 AM, Michael Havens <bmike1 at gmail.com>
>>> wrote:
>>>
>>>> I need to get every four digit combination as part of the next
>>>> challenge in bandit. I'm not a programmer so I googled for a solution.
>>>> Please, how do I run this program?
>>>>
>>>> int main(int argc, char** argv){
>>>> int a,b,c,d;
>>>>
>>>> for(a=1; a<5; a++){
>>>> for(b=1; b<5; b++){
>>>> for(c=1; c<5; c++){
>>>> for(d=1; d<5; d++){
>>>> if(!(a==b || a==c || a==d || b==c || b==d || c==d))
>>>> printf("%d%d%d%d
>>>> ",a,b,c,d);
>>>> }
>>>> }
>>>> }
>>>> }
>>>>
>>>> return 0;
>>>> }
>>>> :-)~MIKE~(-:
>>>>
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>>>
>>>
>>>
>>> --
>>> Love, sex, food, friendship, play, beauty and the simple pleasure of a
>>> cold beer are all well and good, but never forget that the universe is
>>> determined to kill you by whatever means necessary.
>>>
>>>
>>>
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-- 
Todd Millecam
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