how to generate an image only html file in bash

Fri Jul 16 23:33:06 MST 2010

Why not use a bash CGI script for this?

Use this as a starting point

http://www.intuitive.com/wicked/showscript.cgi?073-photoalbum.cgi

I recommend you check out that book too, it's a lot of fun.

Excerpts from Technomage's message of Fri Jul 16 18:59:36 -0700 2010:
> here's what I'd like to do:
> 1. create individual html files for each picture (number not important)
> 2. have each html file display the current image with an href to the 
> next in order image in the directory
> 3. have the first html file linked from inside index.html (such that it 
> shows the first image)
> 4. when the last image in the directory  is reached, that html file has 
> an href that refers to that current image
> 
> can I get a little help here? the bash scripting tutorials are lacking 
> on some points.
> now, what I have is very incomplete and I am not sure how to proceed here:
> 
> ****** bash script  *******
> #!/bin/bash
> #create the index.html file with the type, header and title
> touch index.html
> echo "Content-type: text/html" >> index.html
> echo "" >> index.html
> echo "<html><head><title>picture display shell 
> script</title></head><body>" >> index.html
> 
> # read the directory with the picture files
> for i in *.jpg
>      do
> # this is the part I need to fill in (vreate the individual html files 
> from each listed jpg image
> # write those files, then create the finished index.html that links in 
> the first file.
> 
> done
> # close html file body and final type tag
> echo "</body><html>" >> index.html